Kaluga Svyato-Lavrentiev friary - friary of the Russian Orthodox Church. Article "Лаврентьев монастырь" in Russian Wikipedia has 28.1 points for quality (as of November 1, 2023). The article contains 11 references and 7 sections.
Since the creation of article "Лаврентьев монастырь", its content was written by 18 registered users of Russian Wikipedia and edited by 18 registered Wikipedia users in all languages.
The article is cited 55 times in Russian Wikipedia and cited 55 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from November 1, 2023 (including revision history and pageviews for previous years).
| Best Rank | Russian: #230824 08.2021 |
Global: #2306919 09.2015 |
| Best Rank | Russian: #4541 11.2015 |
Global: #222709 11.2015 |
On 4 June 2024 in multilingual Wikipedia, Internet users most often read articles on the following topics: Kylian Mbappé, Claudia Sheinbaum, ChatGPT, 1989 Tiananmen Square protests and massacre, Jannik Sinner, YouTube, UEFA Euro 2024, June 4, Carlos Alcaraz, Real Madrid CF.
In Russian Wikipedia the most popular articles on that day were: Яндекс, Заворотнюк, Анастасия Юрьевна, YouTube, Чернышёв, Пётр Андреевич, Чилингаров, Артур Николаевич, Годовщины свадьбы, Турчак, Андрей Анатольевич, Мбаппе, Килиан, Раневская, Фаина Георгиевна, Республика Алтай.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from November, 2023. When calculating current popularity and AI of articles data from October 2023 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2023... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(16.06+6.04+46.15+35+37.42)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
